infinity.o3 Posted July 14, 2005 Author Report Share Posted July 14, 2005 die sia. tis coming monday i ned to hand up tis project. n i hv nt the report. hv ur do? i onli noe tt our class is the last class to enrol to tp. LOL. Quote Link to comment Share on other sites More sharing options...
majorabak Posted July 14, 2005 Report Share Posted July 14, 2005 hey all frm etcm rite? haiz ept SO SIANZ :'( Quote Link to comment Share on other sites More sharing options...
infinity.o3 Posted July 14, 2005 Author Report Share Posted July 14, 2005 when is ur date line? i nt from etcm. last wk term test. math ur noe how to do? Quote Link to comment Share on other sites More sharing options...
infinity.o3 Posted July 14, 2005 Author Report Share Posted July 14, 2005 hey, can i replace LM719 to LM7805?? plz reply. thx. =)) Quote Link to comment Share on other sites More sharing options...
thefinalaeon Posted July 14, 2005 Report Share Posted July 14, 2005 maths can pass la... so easy paper but no time... sian... antes, can we replace 7905 with 7805 and 7915 to 7815? please reply thanks alot Quote Link to comment Share on other sites More sharing options...
timothy Posted July 14, 2005 Report Share Posted July 14, 2005 Hi everyone!Base on what the teacher had teached,the 78series is for positive volt.For example 7815 is positive 15 volt.Therefore,79 series is for negative volt.For example 7905 is negative 5 volt.So you have to change the voltage regulator.Then i thinking that the Zener diode can be remove since it is to prevent getting inverse voltage.Er...anybody has a better idea? Quote Link to comment Share on other sites More sharing options...
majorabak Posted July 14, 2005 Report Share Posted July 14, 2005 heyz manz... i dun tink need zener diode... but i tink muz connect the gnd pin of teh -5V regulator to the 0V wire and the input of teh -5V regulator to the output of the -15V regulator... tat is what i tink lah but i may be wrong... the nthe output of ur -5V regulator is ur -5V output supply lorz... i still dunno where to c0onnect extra capacitors for the -5V regulator... ai yah i not sure lah... n also r the c5 n c6 capacitors electrolytic capacitors too?WAH SUPER STRESS LIAOZ SOMEONE HELP PLZ Quote Link to comment Share on other sites More sharing options...
Guest SM2GXN Posted July 14, 2005 Report Share Posted July 14, 2005 Hi!You guys should have started a bit earlier with your EPT project ::) Quote Link to comment Share on other sites More sharing options...
Luffy Posted July 14, 2005 Report Share Posted July 14, 2005 The function of the diode is to provide only 1 pave for current flow. Since the voltage after a step down from the transformer is AC, the diode is essential to change this AC voltage to DC voltage.To have a better ideaThe graph of the output voltage after step down is actually a sine curve. After passing through the diode, the resultant graph will be a sine curve w/o the negative/positive (depends on direction of diode) part of the curve. So it is necessary to have the present of diode to convert AC voltage to pusalting DC voltageAids your researchTo get better idea of the concept of a triple output power supply, i suggest that you break up the research into different part. We noe that a power supply needs- Transformer to step down AC voltage from the power unit to the required amount - Retifier to convert AC voltage to pulsating DC voltage - Filter to convert this pulsating voltage to pure DC voltage- Voltage regulator to direct the desire output voltageSo it is better that you guyz search through the net to get ideas of these sector. After understanding the function of Quote Link to comment Share on other sites More sharing options...
infinity.o3 Posted July 14, 2005 Author Report Share Posted July 14, 2005 it ez. but i did nt complete my test. "-.- i nv even touch on the last question. :'(whr is all the pro ppl ar? y left sg ppl here? Quote Link to comment Share on other sites More sharing options...
POOH Posted July 16, 2005 Report Share Posted July 16, 2005 hey all..finished wif ur projects?i'm still very confused...so wad if we need capacitor but how do we how much farad or volt to use...can dun use transformer...ahhh.......stress.... Quote Link to comment Share on other sites More sharing options...
sianz Posted July 16, 2005 Report Share Posted July 16, 2005 hey do u have any idea on where is the -5v position?pretty blurred.... Quote Link to comment Share on other sites More sharing options...
BabyPrince Posted July 18, 2005 Report Share Posted July 18, 2005 helloo...Cn any1 juz summarise the whole ting..? Quote Link to comment Share on other sites More sharing options...
howly Posted July 18, 2005 Report Share Posted July 18, 2005 wah...sianz...so many parts..see liao oso blur. if not for that 10%(EPT).... Quote Link to comment Share on other sites More sharing options...
ante Posted July 18, 2005 Report Share Posted July 18, 2005 Hi guys,I think I need a new dictionary here! ;D Quote Link to comment Share on other sites More sharing options...
audioguru Posted July 18, 2005 Report Share Posted July 18, 2005 Hi Ante,A dictionary won't help you understand what these kids are saying. Their teacher should teach them English and grammar before teaching them that power supplies have a rated output current. ;D ;D Quote Link to comment Share on other sites More sharing options...
ante Posted July 18, 2005 Report Share Posted July 18, 2005 Hi Audioguru,This kind of scrambled letters should be banned! ;D I agree English first then manners! ;D ;D Quote Link to comment Share on other sites More sharing options...
noobgod Posted July 19, 2005 Report Share Posted July 19, 2005 hi guys,Can anyone give a detail explain of how this circuit works... Thank in advance Quote Link to comment Share on other sites More sharing options...
Guest SM2GXN Posted July 19, 2005 Report Share Posted July 19, 2005 Hi!Try post 6 under this topic, not much but it might help you. Quote Link to comment Share on other sites More sharing options...
noobgod Posted July 19, 2005 Report Share Posted July 19, 2005 ok... i much understand the circuit... another problem is what is the use of the of the other C4 and C3(Capacitors). Quote Link to comment Share on other sites More sharing options...
Guest SM2GXN Posted July 19, 2005 Report Share Posted July 19, 2005 C3 and C4 are required If IC1 or IC2 are located far from filter capacitors C1 and C2. Quote Link to comment Share on other sites More sharing options...
noobgod Posted July 20, 2005 Report Share Posted July 20, 2005 ok.... so c3 and c4 can be remove if IC1 and IC2 are close to C1 and C2.... how far is consider far?? Quote Link to comment Share on other sites More sharing options...
BabyPrince Posted July 20, 2005 Report Share Posted July 20, 2005 thank so much to all who contributed in this discussion to contrust a triple output power supply..i've understand much more.. Quote Link to comment Share on other sites More sharing options...
strangie Posted July 20, 2005 Report Share Posted July 20, 2005 sorry.... can anyone tell me what is the operation on the triple dc power supply?And does it operate? Quote Link to comment Share on other sites More sharing options...
macchiaazzurro Posted July 21, 2005 Report Share Posted July 21, 2005 hi, new to here too. Thanks for the help of the Electronics PRo here.I'm also from TP and i think that you all should do the explantation on the operation of power supply yourself. It will help you in the further too. Don't just think of copying. Hehe TP students must not violate copyright laws man. (hint: use your EPT book to guide you, its more or less in the book.)Well, thanks again. Will be back again in the near future. LOL. Quote Link to comment Share on other sites More sharing options...
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