leedude Posted February 13, 2007 Report Share Posted February 13, 2007 hi, i have just started with electronics, and i was wondering, is there a component out there that would sort of strip off power from a power supply to give a 5v output, as the power supply dropped from 12v?is this called a zener diode or something? Quote Link to comment Share on other sites More sharing options...
ante Posted February 14, 2007 Report Share Posted February 14, 2007 A zener diode might work for low currents and low stability requirements but an LM7805 (there are many others too) will supply more current and high stability! Quote Link to comment Share on other sites More sharing options...
leedude Posted February 20, 2007 Author Report Share Posted February 20, 2007 hmm..ok, i have refined the concept a little,i need the power supply to accomodate an lcd(consumes about 250ma). The input must be a 9v battery, and it must produce an output of 5v. what should i use to build this supply? could i use this: http://www.maplin.co.uk/module.aspx?detail=full&ModuleNo=46321&doy=20m2#more_infoif so, what caps/other components do i use with it? a circuit diagram would be nice. Quote Link to comment Share on other sites More sharing options...
audioguru Posted February 20, 2007 Report Share Posted February 20, 2007 What kind of LCD display consumes 250ma? It must have a very bright light in it.A little 9V alkaline battery can supply 250mA for only a short amount of time. The low dropout 5V regulator will work fine for a little more than one hour.The circuit diagram for the low dropout 5V regulator is in its datasheet that is in your Maplin link. Use two tantalum capacitors as shown. Quote Link to comment Share on other sites More sharing options...
ante Posted February 21, 2007 Report Share Posted February 21, 2007 You must mean 250uA which is more realistic! Quote Link to comment Share on other sites More sharing options...
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