ren_zokuken01 Posted May 13, 2013 Report Share Posted May 13, 2013 so i have this electric device that can generate about hundreds of kV of electricity, but low currents. i'd say about tens of milliamperes??i only need to measure the current. i was thinking of simply using my digital multimeter, so sure, my multimeter can take it coz it's rated to go up until 10A. the thing it's fuse is rated up to only 250V??so, can i simply remove the fuse from the holder and simply short it? since i already know the current is only gonna be within tens of milliamps? if i do so, can i be sure that the high voltage won't damage my multimeter?? Quote Link to comment Share on other sites More sharing options...
ren_zokuken01 Posted May 13, 2013 Author Report Share Posted May 13, 2013 how about a semiconductor device that can limit the flow of very high voltage to an upper limit value, but mostly let the current be the same? i guess it also needs to dissipate the heat from said excess voltage very well. does it exist? Quote Link to comment Share on other sites More sharing options...
Hero999 Posted May 14, 2013 Report Share Posted May 14, 2013 No never remove the fuse from the meter.The meter's insulation is only 1kVDC, if you try to measure 100kV, an arc will jump through the case which will both damage it and you'll get a nasty shock. HaddyS 1 Quote Link to comment Share on other sites More sharing options...
ren_zokuken01 Posted May 17, 2013 Author Report Share Posted May 17, 2013 No never remove the fuse from the meter.The meter's insulation is only 1kVDC, if you try to measure 100kV, an arc will jump through the case which will both damage it and you'll get a nasty shock.thought so..... T_Twhat about my idea of a semiconductor device (somewhat like a diode)?? HaddyS 1 Quote Link to comment Share on other sites More sharing options...
Elex518 Posted February 3, 2019 Report Share Posted February 3, 2019 Simplest way is to add 1 ohm high voltage resistor between the wire...measure the voltage drop across resistor....use the formula I = V/R to calculate the current. Check here for more repair tips --> https://elex518.blogspot.com/ Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.